Question

If the density of water is 1 g $cm^{-3}$ then the volume occupied by one molecule of water is approximately

• A. $18 \,cm^3$
• B. $22400$ $cm^3$
• C. $6.02 \times 10^{-23} \,cm^3$
• D. $3.0 \times 10^{-23} cm^3$

Answer 1

Answer: (D)

Mass of $1$ molecule of water
$=\frac{GMM}{N_{0}}=\frac{18}{6.02\times10^{23}} g $
$\therefore $ Volume of $1$ molecule of water $=\frac{\text{Mass}}{\text{Density}}$
$=\frac{18\times10^{-23}}{6.02\times1}=3.0\times10^{-23}$ mL