Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
If the degree of association is 70 % for the reaction 2 A leftharpoons(A)2 the van't-Hoff factor for the solute A is
Q. If the degree of association is
70%
for the reaction
2
A
⇌
(
A
)
2
the van't-Hoff factor for the solute
A
is
2475
200
TS EAMCET 2018
Report Error
A
0.30
B
0.70
C
0.35
D
0.65
Solution:
2
A
⇌
(
A
)
2
van't-Hoff factor
(
i
)
70%
=
0.7
per unit, i.e.
α
=
0.70
(Given),
where,
α
=
degree of association
n
=
number of units undergo for association
i
=
(
1
−
α
)
+
n
α
⇒
(
1
−
0.70
)
+
2
0.70
i
=
0.30
+
0.35
⇒
0.65