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Chemistry
If the degree of association is 70 % for the reaction 2 A leftharpoons(A)2 the van't-Hoff factor for the solute A is
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Q. If the degree of association is $70 \%$ for the reaction $2\, A \rightleftharpoons(A)_{2}$ the van't-Hoff factor for the solute $A$ is
TS EAMCET 2018
A
0.30
B
0.70
C
0.35
D
0.65
Solution:
$2 A \rightleftharpoons(A)_{2}$ van't-Hoff factor $(i)$
$70 \%=0.7$ per unit, i.e.
$\alpha=0.70$ (Given),
where, $\alpha=$ degree of association
$n=$ number of units undergo for association
$i=(1-\alpha)+\frac{\alpha}{n}$
$\Rightarrow (1-0.70)+\frac{0.70}{2}$
$i=0.30+0.35 \Rightarrow 0.65$