If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is 4 mathringA the circumference of the orbit is

Question

If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is 4 mathringA the circumference of the orbit is (A)  4 mathringA  (B)  4 nm  (C)  16 mathringA (D)  16 nm

Tardigrade Admin · Accepted Answer

de-Broglie wavelength, λ=(2 π rn/n) ∴ The circumference of the orbit, 2 π rn=λ × n=4 × 4=16 mathringA

Q. If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is $4 \overset{˚}{A}$ the circumference of the orbit is

$4 \overset{˚}{A}$

$4 nm$

$16 \overset{˚}{A}$

$16 nm$

de-Broglie wavelength, $λ = \frac{2 π r _{n}}{n}$
$∴$ The circumference of the orbit,
$2 π r_{n} = λ \times n = 4 \times 4 = 16 \overset{˚}{A}$

Q. If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is 4A˚ the circumference of the orbit is

4A˚

4nm

16A˚

16nm