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  4. If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is 4 mathringA the circumference of the orbit is

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Q. If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is $ 4\,\mathring{A}$ the circumference of the orbit is

Chhattisgarh PMTChhattisgarh PMT 2010

Solution:

de-Broglie wavelength, $\lambda=\frac{2 \pi r_{n}}{n} $
$\therefore $ The circumference of the orbit,
$2 \pi r_{n}=\lambda \times n=4 \times 4=16 \,\mathring{A}$