If the concentration of glucose (C6H12O6) in blood is 0.9 g L-1, what will be the molarity of glucose in blood?

Question

If the concentration of glucose (C6H12O6) in blood is 0.9 g L-1, what will be the molarity of glucose in blood? (A) 5 M (B) 50 M (C) 0.005 M (D) 0.5 M

Tardigrade Admin · Accepted Answer

Molarity = (WB (in g)/MB( in g mol-1) × text Volume of solution (in L)) (Conc. (in g L-1)/MB (in g mol-1)) = (0.9/180) = 0.005 M (∴ Molar mass of C6H12O6=180 g mol-1)

Q. If the concentration of glucose $(C_{6} H_{12} O_{6})$ in blood is $0.9 g L^{- 1}$ , what will be the molarity of glucose in blood?

$5 M$

$50 M$

$0.005 M$

$0.5 M$

Molarity $= \frac{W _{B} ( in g )}{M _{B} ( in g m o l ^{- 1} ) \times Volume of solution (in L )}$
$\frac{C o n c . ( in g L ^{- 1} )}{M _{B} ( in g m o l ^{- 1} )} = \frac{0.9}{180} = 0.005 M$
( $∴$ Molar mass of $C_{6} H_{12} O_{6} = 180 g m o l^{- 1}$ )

Q. If the concentration of glucose (C6​H12​O6​) in blood is 0.9gL−1, what will be the molarity of glucose in blood?

5M

50M

0.005M

0.5M