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Chemistry
If the concentration of glucose (C6H12O6) in blood is 0.9 g L-1, what will be the molarity of glucose in blood?
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Q. If the concentration of glucose $(C_{6}H_{12}O_{6})$ in blood is $0.9\, g\, L^{-1}$, what will be the molarity of glucose in blood?
Some Basic Concepts of Chemistry
A
$5\, M$
11%
B
$50\, M$
12%
C
$0.005\, M$
59%
D
$0.5\, M$
18%
Solution:
Molarity $ = \frac {W_B (in\, g)}{M_B( in \, g\, mol^{-1}) \times {\text{ Volume of solution (in $L$)}}}$
$\frac {Conc. (in \,g\, L^{-1})}{M_B (in \,g\, mol^{-1})} = \frac{0.9}{180} = 0.005\,M$
($\therefore $ Molar mass of $ C_6H_{12}O_6=180\,g\,mol^{-1}$)