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Q. If the concentration of glucose $(C_{6}H_{12}O_{6})$ in blood is $0.9\, g\, L^{-1}$, what will be the molarity of glucose in blood?

Some Basic Concepts of Chemistry

Solution:

Molarity $ = \frac {W_B (in\, g)}{M_B( in \, g\, mol^{-1}) \times {\text{ Volume of solution (in $L$)}}}$
$\frac {Conc. (in \,g\, L^{-1})}{M_B (in \,g\, mol^{-1})} = \frac{0.9}{180} = 0.005\,M$
($\therefore $ Molar mass of $ C_6H_{12}O_6=180\,g\,mol^{-1}$)