If the collision between the incident α-particle whose kinetic energy is T and electric charge 2 e and the nucleus were head on. The correct relation between the distance of closest approach D and T is

Question

If the collision between the incident α-particle whose kinetic energy is T and electric charge 2 e and the nucleus were head on. The correct relation between the distance of closest approach D and T is (A) D propto (1/ T ) (B) D propto T (C) D propto T 2 (D) D propto (1/ T 2)

Tardigrade Admin · Accepted Answer

T =2 Ze 2 / 4 π ε0 D T propto (1/D)

Q. If the collision between the incident $α$ -particle whose kinetic energy is $T$ and electric charge $2 e$ and the nucleus were head on. The correct relation between the distance of closest approach $D$ and $T$ is

$D \propto \frac{1}{T}$

$D \propto T$

$D \propto T^{2}$

$D \propto \frac{1}{T ^{2}}$

$T = 2 Z e^{2} /4 π ε_{0} D$
$T \propto \frac{1}{D}$

Q. If the collision between the incident α-particle whose kinetic energy is T and electric charge 2e and the nucleus were head on. The correct relation between the distance of closest approach D and T is

D∝T1​

D∝T

D∝T2

D∝T21​