1. Tardigrade
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  4. If the collision between the incident α-particle whose kinetic energy is T and electric charge 2 e and the nucleus were head on. The correct relation between the distance of closest approach D and T is

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Q. If the collision between the incident $\alpha$-particle whose kinetic energy is $T$ and electric charge $2 e$ and the nucleus were head on. The correct relation between the distance of closest approach $D$ and $T$ is

Atoms

Solution:

$T =2 Ze ^2 / 4 \pi \varepsilon_0 D$
$T \propto \frac{1}{D}$