If the cathode-anode potential difference in an X -ray tube be 105 V, then the maximum energy of X -ray photon can be

Question

If the cathode-anode potential difference in an X -ray tube be 105 V, then the maximum energy of X -ray photon can be (A) 105 J (B) 105 MeV (C) 10-1 MeV (D) 105 KeV

Tardigrade Admin · Accepted Answer

Since λ min =(12375/V) mathringA =(12375/105) mathringA=0.123 mathringA E max =(h c/λ min ) On putting the values. E max ≅ 10-1 MeV.

Q. If the cathode-anode potential difference in an $X$ -ray tube be $1 0^{5} V$ , then the maximum energy of $X$ -ray photon can be

$1 0^{5} J$

$1 0^{5} M e V$

$1 0^{- 1} M e V$

$1 0^{5} Ke V$

Since $λ_{m i n} = \frac{12375}{V} \overset{˚}{A}$
$= \frac{12375}{1 0 ^{5}} \overset{˚}{A} = 0.123 \overset{˚}{A}$
$E_{m a x} = \frac{h c}{λ _{m i n}}$
On putting the values. $E_{m a x} ≅ 1 0^{- 1} M e V$ .

Q. If the cathode-anode potential difference in an X -ray tube be 105V, then the maximum energy of X -ray photon can be

105J

105MeV

10−1MeV

105KeV