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Physics
If the cathode-anode potential difference in an X -ray tube be 105 V, then the maximum energy of X -ray photon can be
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Q. If the cathode-anode potential difference in an $X$ -ray tube be $10^{5} V$, then the maximum energy of $X$ -ray photon can be
Dual Nature of Radiation and Matter
A
$10^{5} J$
B
$10^{5} MeV$
C
$10^{-1} MeV$
D
$10^{5} KeV$
Solution:
Since $\lambda_{\min }=\frac{12375}{V} \mathring{A}$
$=\frac{12375}{10^{5}} \mathring{A}=0.123\, \mathring{A}$
$E_{\max }=\frac{h c}{\lambda_{\min }}$
On putting the values. $E_{\max } \cong 10^{-1} MeV$.