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Q. If the cathode-anode potential difference in an $X$ -ray tube be $10^{5} V$, then the maximum energy of $X$ -ray photon can be

Dual Nature of Radiation and Matter

Solution:

Since $\lambda_{\min }=\frac{12375}{V} \mathring{A}$
$=\frac{12375}{10^{5}} \mathring{A}=0.123\, \mathring{A}$
$E_{\max }=\frac{h c}{\lambda_{\min }}$
On putting the values. $E_{\max } \cong 10^{-1} MeV$.