If the bulk modulus of water is 2100 M Pa, then speed of sound in water is (take the density of water, ρ =1000 kg m- 3 )

Question

If the bulk modulus of water is 2100 M Pa, then speed of sound in water is (take the density of water, ρ =1000 kg m- 3 ) (A) 1320 ms- 1 (B) 1450 ms- 1 (C) 1580 ms- 1 (D) 1630 ms- 1

Tardigrade Admin · Accepted Answer

Speed of sound in water is given by, v=√(B/ρ ) ∴ v=√(2100 × 106/1000)=√2 .1 × 106 or v=1.45× 103=1450 ms- 1

Q. If the bulk modulus of water is $2100 M P a,$ then speed of sound in water is (take the density of water, $ρ = 1000 k g m^{- 3}$ )

$1320 m s^{- 1}$

$1450 m s^{- 1}$

$1580 m s^{- 1}$

$1630 m s^{- 1}$

Speed of sound in water is given by,
$v = \frac{B}{ρ}$
$∴ v = \frac{2100 \times 1 0 ^{6}}{1000} = 2.1 \times 1 0^{6}$
or $v = 1.45 \times 1 0^{3} = 1450 m s^{- 1}$

Q. If the bulk modulus of water is 2100MPa, then speed of sound in water is (take the density of water, ρ=1000kgm−3 )

1320ms−1

1450ms−1

1580ms−1

1630ms−1