If the Boolean expression (p ⊕ q)∧ (∼ p odot q) is equivalent to p ∧ q where ⊕, odot ∈ ∧ , ∨ , then the ordered pair (⊕ , odot) is:

Question

If the Boolean expression (p ⊕ q)∧ (∼ p odot q) is equivalent to p ∧ q where ⊕, odot ∈ ∧ , ∨ , then the ordered pair (⊕ , odot) is: (A) ( ∧ , ∨ ) (B) ( ∨ , ∨ ) (C) ( ∧ , ∧ ) (D) ( ∨, ∧ )

Tardigrade Admin · Accepted Answer

Correct answer is (a) ( ∧ , ∨ )

Q. If the Boolean expression $(p \oplus q) \land (\sim p ⊙ q)$ is equivalent to $p \land q$ where $\oplus, ⊙ \in {\land, \lor}$ , then the ordered pair $(\oplus, ⊙)$ is:

$(\land, \lor)$

$(\lor, \lor)$

$(\land, \land)$

$(\lor, \land)$

Correct answer is (a) $(\land, \lor)$

Q. If the Boolean expression (p⊕q)∧(∼p⊙q) is equivalent to p∧q where ⊕,⊙∈{∧,∨} , then the ordered pair (⊕,⊙) is:

(∧,∨)

(∨,∨)

(∧,∧)

(∨,∧)