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  4. If the Boolean expression (p ⊕ q)∧ (∼ p odot q) is equivalent to p ∧ q where ⊕, odot ∈ ∧ , ∨ , then the ordered pair (⊕ , odot) is:

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Q. If the Boolean expression $\left(p \oplus q\right)\wedge \left(\sim p \odot q\right) $ is equivalent to $p \wedge q$ where $\oplus, \odot \; \in \{ \wedge , \vee \}$ , then the ordered pair $(\oplus , \odot)$ is:

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Solution:

Correct answer is (a) $( \wedge , \vee )$