Question

If the bond distance in chlorine molecule $\left(C{l}_2\right)$ is $198pm$, then the atomic radius of chlorine is

• A. $198pm$
• B. $49.5pm$
• C. $99pm$
• D. $24.75pm$

Answer 1

Answer: (C)

Atomic radius of $Cl$ atom $=\frac{\text{ Bond distance in }C{l}_2}{2}$
$=\frac{198}{2}=99pm$