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  4. If the bond distance in chlorine molecule ( Cl 2) is 198 pm, then the atomic radius of chlorine is

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Q. If the bond distance in chlorine molecule $\left( Cl _{2}\right)$ is $198 \, pm$, then the atomic radius of chlorine is

Classification of Elements and Periodicity in Properties

Solution:

Atomic radius of $Cl$ atom $=\frac{\text { Bond distance in } Cl _{2}}{2}$
$=\frac{198}{2}=99 \,pm$