If the best and the worst paper never appear together, then six examination papers can be arranged in how many ways

Question

If the best and the worst paper never appear together, then six examination papers can be arranged in how many ways (A) 120 (B) 480 (C) 240 (D) None of these

Tardigrade Admin · Accepted Answer

If the best and worst appear always together, the number of ways

5! \times 2

Therefore, required number of ways = Total number of ways without any restrictions - number of ways when best and worst papers are together

= 6! - 5! \times 2 = 480

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Q. If the best and the worst paper never appear together, then six examination papers can be arranged in how many ways

120

480

240

None of these

If the best and worst appear always together, the number of ways 5!×2 Therefore, required number of ways = Total number of ways without any restrictions - number of ways when best and worst papers are together =6!−5!×2=480.

If the best and worst appear always together, the number of ways $5! \times 2$
Therefore, required number of ways = Total number of ways without any restrictions - number of ways when best and worst papers are together $= 6! - 5! \times 2 = 480$ .