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Q. If the best and the worst paper never appear together, then six examination papers can be arranged in how many ways

Permutations and Combinations

Solution:

If the best and worst appear always together, the number of ways $5 ! \times 2$
Therefore, required number of ways = Total number of ways without any restrictions - number of ways when best and worst papers are together $=6 !-5 ! \times 2=480$.