Question

If the atmospheric pressure is $P_a$, then the pressure $P$ at depth $h$ below the surface of a liquid of density $p$ open to the atmosphere is

• A. $P_a-\frac{\rho gh}{2}$
• B. $Pa-pgh$
• C. $P_a$
• D. $P_a+\frac{\rho gh}{2}$
• E. $P_a+pgh$

Answer 1

Answer: (E)

Correct answer is (e) $P_a+pgh$