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Physics
If the atmospheric pressure is Pa, then the pressure P at depth h below the surface of a liquid of density p open to the atmosphere is
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Q. If the atmospheric pressure is $P_a$, then the pressure $P$ at depth $h$ below the surface of a liquid of density $p$ open to the atmosphere is
KEAM
KEAM 2010
A
$P_{a}-\frac{\rho gh}{2}$
B
$Pa - pgh$
C
$P_a$
D
$P_{a}+\frac{\rho gh}{2}$
E
$P_a + pgh$
Solution:
Correct answer is (e) $P_a + pgh$