If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be

Question

If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be (A) increasing by a factor of 2 (B) decreasing by a factor of 2 (C) decreasing by a factor of 1/4 (D) unchanged

Tardigrade Admin · Accepted Answer

Intensity propto( amplitude )2 and also intensity propto(. frequency) 2. Therefore original I propto A2 ω2 I prime propto 4 A2 (ω2/16) i.e., (1/4) I

Q. If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be

increasing by a factor of 2

decreasing by a factor of 2

decreasing by a factor of 1/4

unchanged

Intensity $\propto ($ amplitude $)^{2}$ and also intensity $\propto ($ frequency) $^{2}$ .
Therefore original $I \propto A^{2} ω^{2}$
$I^{'} \propto 4 A^{2} \frac{ω ^{2}}{16}$ i.e., $\frac{1}{4} I$

Q. If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be

increasing by a factor of 2

decreasing by a factor of 2

decreasing by a factor of 1/4

unchanged

Intensity ∝( amplitude )2 and also intensity ∝( frequency) 2. Therefore original I∝A2ω2 I′∝4A216ω2​ i.e., 41​I

Intensity $\propto ($ amplitude $)^{2}$ and also intensity $\propto ($ frequency) $^{2}$ .
Therefore original $I \propto A^{2} ω^{2}$
$I^{'} \propto 4 A^{2} \frac{ω ^{2}}{16}$ i.e., $\frac{1}{4} I$