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Physics
If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be
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Q. If the amplitude of sound is doubled and the frequency reduced to one fourth, the intensity of sound at the same point will be
AIPMT
AIPMT 1989
Waves
A
increasing by a factor of 2
11%
B
decreasing by a factor of 2
14%
C
decreasing by a factor of 1/4
48%
D
unchanged
27%
Solution:
Intensity $\propto($ amplitude $)^{2}$ and also intensity $\propto\left(\right.$ frequency) ${ }^{2}$.
Therefore original $I \propto A^{2} \omega^{2}$
$I^{\prime} \propto 4 A^{2} \frac{\omega^{2}}{16} $ i.e., $\frac{1}{4} I$