If solubility product of HgSO 4 is 6.4 × 10-5, then its solubility is :

Question

If solubility product of HgSO 4 is 6.4 × 10-5, then its solubility is : (A)  8× 10-3 mol/L  (B)  6.4× 10-5 mol/L  (C)  6.4× 10-3 mol/L  (D)  2.8× 10-6 mol/L

Tardigrade Admin · Accepted Answer

First find the relationship between solubility and solubility product of

H g S O_{4}

, then substitute the values and calculate to find the value of solubility of

H g S O_{4}

.
Let the solubility of

H g S O_{4}

be

s m o l / L

H g S O_{4} ⇌ H g^{2 +} + S O_{4}^{2 -}

K_{s p} = [H g^{2 + 1} [S O_{4}^{2 -}]

= s \times s

= s^{2}

or

s = K_{s p}

= 6.4 \times 1 0^{- 5}

= 8 \times 1 0^{- 3} m o l / L

Q. If solubility product of $H g S O_{4}$ is $6.4 \times 1 0^{- 5}$ , then its solubility is :

$8 \times 10^{- 3} m o l / L$

$6.4 \times 10^{- 5} m o l / L$

$6.4 \times 10^{- 3} m o l / L$

$2.8 \times 10^{- 6} m o l / L$

Q. If solubility product of HgSO4​ is 6.4×10−5, then its solubility is :

8×10−3mol/L

6.4×10−5mol/L

6.4×10−3mol/L

2.8×10−6mol/L

Q. If solubility product of $H g S O_{4}$ is $6.4 \times 1 0^{- 5}$ , then its solubility is :

$8 \times 10^{- 3} m o l / L$

$6.4 \times 10^{- 5} m o l / L$

$6.4 \times 10^{- 3} m o l / L$

$2.8 \times 10^{- 6} m o l / L$