If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is

Question

If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is (A) 6!7! (B) (6!)2 (C) (7!)2 (D) 7!

Tardigrade Admin · Accepted Answer

7 women can be arranged around a circular table in 6! ways. Among these 7 men can sit in 7! ways. Hence, number of seating arrangement = 7! × 6!

Q. If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is

$6! 7!$

$(6!)^{2}$

$(7!)^{2}$

$7!$

7 women can be arranged around a circular table in 6! ways.
Among these 7 men can sit in 7! ways. Hence, number of seating arrangement $= 7! \times 6!$

Q. If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is

6!7!

(6!)2

(7!)2

7!

7 women can be arranged around a circular table in 6! ways. Among these 7 men can sit in 7! ways. Hence, number of seating arrangement =7!×6!

$6! 7!$

$(6!)^{2}$

$(7!)^{2}$

$7!$

7 women can be arranged around a circular table in 6! ways.
Among these 7 men can sit in 7! ways. Hence, number of seating arrangement $= 7! \times 6!$