Question

If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is

• A. $6!7!$
• B. $\left(6!\right)^{2}$
• C. $\left(7!\right)^{2}$
• D. $7!$

Answer 1

Answer: (A)

7 women can be arranged around a circular table in 6! ways.
Among these 7 men can sit in 7! ways. Hence, number of seating arrangement $= 7! \times 6!$