If rope of lift breaks suddenly the tension exerted by the surface of lift will be: (a = acceleration of lift)

Question

If rope of lift breaks suddenly the tension exerted by the surface of lift will be: (a = acceleration of lift) (A) m (g + a)  (B) mg (C) m(g - a) (D) Zero

Tardigrade Admin · Accepted Answer

After breaking the rope the lift undergoes free fall, hence acceleration becomes zero T = m (g - a) ⇒ T = m(g - g) = 0

Q. If rope of lift breaks suddenly the tension exerted by the surface of lift will be: (a = acceleration of lift)

$m (g + a)$

$m g$

$m (g - a)$

Zero

After breaking the rope the lift undergoes free fall,
hence acceleration becomes zero
$T = m (g - a)$
$\Rightarrow T = m (g - g) = 0$

Q. If rope of lift breaks suddenly the tension exerted by the surface of lift will be: (a = acceleration of lift)

m(g+a)

mg

m(g−a)

Zero

After breaking the rope the lift undergoes free fall, hence acceleration becomes zero T=m(g−a) ⇒T=m(g−g)=0

$m (g + a)$

$m g$

$m (g - a)$

After breaking the rope the lift undergoes free fall,
hence acceleration becomes zero
$T = m (g - a)$
$\Rightarrow T = m (g - g) = 0$