If refractive index of red, violet and yellow lights are 1.42, 1.62 and 1.50 respectively for a medium. Its dispersive power will be

Question

If refractive index of red, violet and yellow lights are 1.42, 1.62 and 1.50 respectively for a medium. Its dispersive power will be (A) 0.4 (B) 0.3 (C) 0.2 (D) 0.1

Tardigrade Admin · Accepted Answer

ω=(μV-μR/μY-1)=(1.62-1.42/1.5-1)=0.4

Q. If refractive index of red, violet and yellow lights are $1.42, 1.62$ and $1.50$ respectively for a medium. Its dispersive power will be

0.4

0.3

0.2

0.1

$ω = \frac{μ _{V} - μ _{R}}{μ _{Y} - 1} = \frac{1.62 - 1.42}{1.5 - 1} = 0.4$

Q. If refractive index of red, violet and yellow lights are 1.42,1.62 and 1.50 respectively for a medium. Its dispersive power will be

0.4

0.3

0.2

0.1

ω=μY​−1μV​−μR​​=1.5−11.62−1.42​=0.4

Q. If refractive index of red, violet and yellow lights are $1.42, 1.62$ and $1.50$ respectively for a medium. Its dispersive power will be

$ω = \frac{μ _{V} - μ _{R}}{μ _{Y} - 1} = \frac{1.62 - 1.42}{1.5 - 1} = 0.4$