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Q. If refractive index of red, violet and yellow lights are $1.42, \,1.62$ and $1.50$ respectively for a medium. Its dispersive power will be

Ray Optics and Optical Instruments

Solution:

$\omega=\frac{\mu_{V}-\mu_{R}}{\mu_{Y}-1}=\frac{1.62-1.42}{1.5-1}=0.4$