Question

If reduction factor of a tangent galvanometer is $900mA$, then the current through it to produce a deflection of $45^{\circ }$ is

• A. 600 mA
• B. 700 mA
• C. 750 mA
• D. 900 mA

Answer 1

Answer: (D)

Current $(I)$ flowing in a tangent galvanometer is given by
$I=k\tan \theta \text{. }$
Given, $k$ is reduction factor
$\left(k=900mA=900\times 10^{-3}A\right),\theta =45^{\circ }$
$\therefore I=900\times 10^{-3}\times \tan 45^{\circ }$
$\Rightarrow I=900mA$