Question

If radius of the sphere is (5.3 $\pm$ 0. 1) cm. Then percentage error in its volume will be

• A. $3+6.01\times \frac{100}{5.3}$
• B. $\frac{1}{3}\times 0.01\times \frac{100}{5.3}$
• C. $\left(\frac{3\times 0.1}{5.3}\right)\times 100$
• D. $\frac{0.1}{5.3}\times 100$

Answer 1

Answer: (C)

Volume of sphere (V) = $\frac{4}{3}\pi r^3$
% error m volume = $\frac{3\times △r}{r}\times 100$
= $\left(\frac{3\times 0.1}{5.3}\right)\times 100$