Question

If radius of the sphere is (5.3 $ \pm $ 0. 1) cm. Then percentage error in its volume will be

• A. $3 + 6.01 \times \frac{ 100 }{ 5.3 } $
• B. $ \frac{ 1}{ 3} \times 0.01 \times \frac{100 }{ 5.3 } $
• C. $ \bigg( \frac{ 3 \times 0.1 }{ 5.3} \bigg) \times 100 $
• D. $ \frac{ 0.1 }{ 5.3} \times 100$

Answer 1

Answer: (C)

Volume of sphere (V) = $ \frac{ 4 }{ 3} \pi r^3 $
% error m volume = $ \frac{ 3 \times \triangle r }{ r } \times 100 $
= $ \bigg( \frac{ 3 \times 0.1 }{ 5.3 } \bigg) \times 100 $