Question

If p and q are the roots of the equation $x^2+pq=(p+1)x,$ , then $q$ is equal to:

• A. -1
• B. 2
• C. 1
• D. -2

Answer 1

Answer: (C)

Since, p and q are the roots of the equation
$x^2+pq=(p+1)x$
or $x^2-(p+1)x+pq=0$
$\therefore$ $p+q=(p+1)$
$\Rightarrow$ $q=1$