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  4. If p and q are the roots of the equation x2+pq=(p+1)x, , then q is equal to:

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Q. If p and q are the roots of the equation $ {{x}^{2}}+pq=(p+1)x, $ , then $ q $ is equal to:

Bihar CECEBihar CECE 2005

Solution:

Since, p and q are the roots of the equation
$ {{x}^{2}}+pq=(p+1)x $
or $ {{x}^{2}}-(p+1)x+pq=0 $
$ \therefore $ $ p+q=(p+1) $
$ \Rightarrow $ $ q=1 $