Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If P(A)=0.59, P(B)=0.30 and P(A ∩ B)=0.21 then P(A' ∩ B')=
Q. If
P
(
A
)
=
0.59
,
P
(
B
)
=
0.30
and
P
(
A
∩
B
)
=
0.21
then
P
(
A
′
∩
B
′
)
=
5126
165
KCET
KCET 2021
Probability
Report Error
A
0.11
0%
B
0.38
0%
C
0.32
100%
D
0.35
0%
Solution:
P
(
A
1
∩
B
1
)
=
1
−
P
(
A
∪
B
)
=
1
−
[
0.59
+
0.3
−
0.21
]
=
0.32