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  4. If P(A)=0.59, P(B)=0.30 and P(A ∩ B)=0.21 then P(A' ∩ B')=

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Q. If $P(A)=0.59, P(B)=0.30$ and $P(A \cap B)=0.21$ then $P\left(A^{'} \cap B^{'}\right)=$

KCETKCET 2021Probability

Solution:

$P\left(A^{1} \cap B^{1}\right)=1-P(A \cup B)$
$=1-[0.59+0.3-0.21]$
$=0.32$