Question

If $p>1$ and $q>1$ be such that $\log (p+q)=\log p+\log q$, then the value of $\log (p-1)+\log (q-1)$ is equal to

• A. 0
• B. 1
• C. 2
• D. cannot be determined

Answer 1

Answer: (A)

Given, $p+q=pq$ ......(1)
Now, $\log (p-1)+\log (q-1)=\log (pq-p-q+1)=0[U\mathrm{sing}(1)]$