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Question
Mathematics
If ω is an imaginary cube root of unity, then the value of sin (ω10+ω23) π-(π/4) is
Q. If
ω
is an imaginary cube root of unity, then the value of
sin
{
(
ω
10
+
ω
23
)
π
−
4
π
}
is
211
141
Complex Numbers and Quadratic Equations
Report Error
A
−
2
3
B
−
2
1
C
2
1
D
2
3
Solution:
Using
ω
10
=
ω
,
ω
23
=
ω
2
, we get
sin
{
(
ω
10
+
ω
23
)
π
−
4
π
}
=
sin
(
−
π
−
4
π
)
=
sin
4
π
=
2
1