If object starts from rest and covers angle of 60 rad in 10 sec in circular motion magnitude of angular acceleration will be-

Question

If object starts from rest and covers angle of 60 rad in 10 sec in circular motion magnitude of angular acceleration will be- (A) 1.2 rad / sec 2 (B) 1.5 rad / sec 2 (C) 2 rad / sec 2 (D) 2.5 rad / sec 2

Tardigrade Admin · Accepted Answer

Given, ω0 = 0 θ = 60 rad t = 10 sec let angular acceleration =α Then, θ=ω0 t+(1/2) α t2 Put the values, 60=(1/2) × α × 100 a=1.2 rad / sec 2

Q. If object starts from rest and covers angle of $60$ rad in $10$ sec in circular motion magnitude of angular acceleration will be-

$1.2 r a d / se c^{2}$

$1.5 r a d / se c^{2}$

$2 r a d / se c^{2}$

$2.5 r a d / se c^{2}$

Given, $ω_{0}$ = 0
$θ = 60 r a d$
$t = 10 sec$
let angular acceleration $= α$
Then,
$θ = ω_{0} t + \frac{1}{2} α t^{2}$
Put the values,
$60 = \frac{1}{2} \times α \times 100$ $a = 1.2 r a d / se c^{2}$

Q. If object starts from rest and covers angle of 60 rad in 10 sec in circular motion magnitude of angular acceleration will be-

1.2rad/sec2

1.5rad/sec2

2rad/sec2

2.5rad/sec2