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Q. If object starts from rest and covers angle of $60$ rad in $10$ sec in circular motion magnitude of angular acceleration will be-

JIPMERJIPMER 2019

Solution:

Given, $\omega_0$ = 0
$\theta = 60\, rad$
$t = 10\, sec$
let angular acceleration $=\alpha$
Then,
$\theta=\omega_{0} t+\frac{1}{2} \alpha t^{2}$
Put the values,
$60=\frac{1}{2} \times \alpha \times 100$ $a=1.2 \,rad / sec ^{2}$