The latent heat of steam = 540 cal/g and the latent heat of ice = 80 cal/g The specific heat of water is 1cal/g∘C Heat lost by xg of steam in condensing =540x ?(i) Heat gained by ice =y×80+y×100=180y ?(ii) Equation (i) and (ii) we get xy=3, so, y:x=3:1