The latent heat of steam = 540 cal/g and the latent heat of ice = 80 cal/g The specific heat of water is $ 1\text{ }cal\text{/}g{}^\circ C $ Heat lost by xg of steam in condensing $ =540x $ ?(i) Heat gained by ice $ =y\times 80+y\times 100=180y $ ?(ii) Equation (i) and (ii) we get $ \frac{y}{x}=3, $ so, $ y:x=3:1 $