If n is the number of carbon atoms in the potassium salt of a carboxylic acid, then the alkene formed on electrolysis of aqueous solution of a salt of a carboxylic acid containing n carbon atoms would have carbon atoms equal to

Question

If n is the number of carbon atoms in the potassium salt of a carboxylic acid, then the alkene formed on electrolysis of aqueous solution of a salt of a carboxylic acid containing n carbon atoms would have carbon atoms equal to (A) n (B) n-1 (C) 2n-1 (D) 2(n-1)

Tardigrade Admin · Accepted Answer

During Kolbe’s electrolysis, two carbon atoms are lost from two carboxylic acid molecules. Therefore, number of carbon atoms in the alkane formed = 2n - 2 = 2(n - 1)

Q. If $n$ is the number of carbon atoms in the potassium salt of a carboxylic acid, then the alkene formed on electrolysis of aqueous solution of a salt of a carboxylic acid containing $n$ carbon atoms would have carbon atoms equal to

n

n-1

2n-1

2(n-1)

During Kolbe’s electrolysis, two carbon atoms are lost from two carboxylic acid molecules. Therefore, number of carbon atoms in the alkane formed $= 2 n - 2 = 2 (n - 1)$

Q. If n is the number of carbon atoms in the potassium salt of a carboxylic acid, then the alkene formed on electrolysis of aqueous solution of a salt of a carboxylic acid containing n carbon atoms would have carbon atoms equal to

n

n-1

2n-1

2(n-1)

During Kolbe’s electrolysis, two carbon atoms are lost from two carboxylic acid molecules. Therefore, number of carbon atoms in the alkane formed =2n−2=2(n−1)

Q. If $n$ is the number of carbon atoms in the potassium salt of a carboxylic acid, then the alkene formed on electrolysis of aqueous solution of a salt of a carboxylic acid containing $n$ carbon atoms would have carbon atoms equal to

During Kolbe’s electrolysis, two carbon atoms are lost from two carboxylic acid molecules. Therefore, number of carbon atoms in the alkane formed $= 2 n - 2 = 2 (n - 1)$