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Q. If $n$ is the number of carbon atoms in the potassium salt of a carboxylic acid, then the alkene formed on electrolysis of aqueous solution of a salt of a carboxylic acid containing $n$ carbon atoms would have carbon atoms equal to

Hydrocarbons

Solution:

During Kolbe’s electrolysis, two carbon atoms are lost from two carboxylic acid molecules. Therefore, number of carbon atoms in the alkane formed $= 2n - 2 = 2(n - 1)$