If mass of CO2 molecule is 44u and Avogadro's number is 6.023× 1023 then mass of one molecule in kg is

Question

If mass of CO2 molecule is 44u and Avogadro's number is 6.023× 1023 then mass of one molecule in kg is (A)  16× 10-28kg  (B)  2.16× 10-22kg  (C)  3.46× 10-28kg  (D)  7.3× 10-26kg

Tardigrade Admin · Accepted Answer

1 mole CO2=44 u ∵ 1u=(1/6.023× 1023)g 44u=(44× 10-3/6.023× 1023)g =7.30× 10-26kg

Q. If mass of $C O_{2}$ molecule is $44 u$ and Avogadro's number is $6.023 \times 10^{23}$ then mass of one molecule in kg is

$16 \times 10^{- 28} k g$

$2.16 \times 10^{- 22} k g$

$3.46 \times 10^{- 28} k g$

$7.3 \times 10^{- 26} k g$

1 mole $C O_{2} = 44 u$
$∵$ $1 u = \frac{1}{6.023 \times 10 ^{23}} g$
$44 u = \frac{44 \times 10 ^{- 3}}{6.023 \times 10 ^{23}} g$
$= 7.30 \times 10^{- 26} k g$

Q. If mass of CO2​ molecule is 44u and Avogadro's number is 6.023×1023 then mass of one molecule in kg is

16×10−28kg

2.16×10−22kg

3.46×10−28kg

7.3×10−26kg