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  4. If mass of CO2 molecule is 44u and Avogadro's number is 6.023× 1023 then mass of one molecule in kg is

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Q. If mass of $ C{{O}_{2}} $ molecule is $44u$ and Avogadro's number is $ 6.023\times {{10}^{23}} $ then mass of one molecule in kg is

Rajasthan PETRajasthan PET 2001

Solution:

1 mole $ C{{O}_{2}}=44\,u $
$ \because $ $ 1u=\frac{1}{6.023\times {{10}^{23}}}g $
$ 44u=\frac{44\times {{10}^{-3}}}{6.023\times {{10}^{23}}}g $
$ =7.30\times {{10}^{-26}}kg $