Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
If mass of CO2 molecule is 44u and Avogadro's number is 6.023× 1023 then mass of one molecule in kg is
Q. If mass of
C
O
2
​
molecule is
44
u
and Avogadro's number is
6.023
×
10
23
then mass of one molecule in kg is
1910
248
Rajasthan PET
Rajasthan PET 2001
Report Error
A
16
×
10
−
28
k
g
B
2.16
×
10
−
22
k
g
C
3.46
×
10
−
28
k
g
D
7.3
×
10
−
26
k
g
Solution:
1 mole
C
O
2
​
=
44
u
∵
1
u
=
6.023
×
10
23
1
​
g
44
u
=
6.023
×
10
23
44
×
10
−
3
​
g
=
7.30
×
10
−
26
k
g