If m1 gram of a metal A displaces m2 gram of another metal B from its salt solution and if the equivalent weights are E1 and E2 respectively then the equivalent weight of A can be expressed by

Question

If m1 gram of a metal A displaces m2 gram of another metal B from its salt solution and if the equivalent weights are E1 and E2 respectively then the equivalent weight of A can be expressed by (A) E1=(m1/m2) × E2 (B) E1=(m2 × E2/m1) (C) E1=(m1 × m2/E2) (D) E1=√(m1/m2) × E2

Tardigrade Admin · Accepted Answer

( text Wt.of metal 1/ text Wt.of metal 2)=( text Eq. wt.of metal 1 / text Eq.wt.of metal 2) i.e., (m1/m2)=(E1/E2) Hence, E1=(m1/m2) × E2

Q. If $m_{1}$ gram of a metal $A$ displaces $m_{2}$ gram of another metal $B$ from its salt solution and if the equivalent weights are $E_{1}$ and $E_{2}$ respectively then the equivalent weight of $A$ can be expressed by

$E_{1} = \frac{m _{1}}{m _{2}} \times E_{2}$

$E_{1} = \frac{m _{2} \times E _{2}}{m _{1}}$

$E_{1} = \frac{m _{1} \times m _{2}}{E _{2}}$

$E_{1} = \frac{m _{1}}{m _{2}} \times E_{2}$

$\frac{Wt.of metal 1}{Wt.of metal 2} = \frac{Eq. wt.of metal 1}{Eq.wt.of metal 2}$

i.e., $\frac{m _{1}}{m _{2}} = \frac{E _{1}}{E _{2}}$

Hence, $E_{1} = \frac{m _{1}}{m _{2}} \times E_{2}$

Q. If m1​ gram of a metal A displaces m2​ gram of another metal B from its salt solution and if the equivalent weights are E1​ and E2​ respectively then the equivalent weight of A can be expressed by

E1​=m2​m1​​×E2​

E1​=m1​m2​×E2​​

E1​=E2​m1​×m2​​

E1​=m2​m1​​×E2​​

Wt.of metal 2 Wt.of metal 1​= Eq.wt.of metal 2 Eq. wt.of metal 1 ​ i.e., m2​m1​​=E2​E1​​ Hence, E1​=m2​m1​​×E2​

Q. If $m_{1}$ gram of a metal $A$ displaces $m_{2}$ gram of another metal $B$ from its salt solution and if the equivalent weights are $E_{1}$ and $E_{2}$ respectively then the equivalent weight of $A$ can be expressed by

$E_{1} = \frac{m _{1}}{m _{2}} \times E_{2}$

$E_{1} = \frac{m _{2} \times E _{2}}{m _{1}}$

$E_{1} = \frac{m _{1} \times m _{2}}{E _{2}}$

$E_{1} = \frac{m _{1}}{m _{2}} \times E_{2}$

$\frac{Wt.of metal 1}{Wt.of metal 2} = \frac{Eq. wt.of metal 1}{Eq.wt.of metal 2}$

i.e., $\frac{m _{1}}{m _{2}} = \frac{E _{1}}{E _{2}}$

Hence, $E_{1} = \frac{m _{1}}{m _{2}} \times E_{2}$