Question

If $m_{1}$ gram of a metal $A$ displaces $m_{2}$ gram of another metal $B$ from its salt solution and if the equivalent weights are $E_{1}$ and $E_{2}$ respectively then the equivalent weight of $A$ can be expressed by

• A. $E_{1}=\frac{m_{1}}{m_{2}} \times E_{2}$
• B. $E_{1}=\frac{m_{2} \times E_{2}}{m_{1}}$
• C. $E_{1}=\frac{m_{1} \times m_{2}}{E_{2}}$
• D. $E_{1}=\sqrt{\frac{m_{1}}{m_{2}} \times E_{2}}$

Answer 1

Answer: (A)

$\frac{\text { Wt.of metal 1}}{\text { Wt.of metal } 2}=\frac{\text { Eq. wt.of metal 1 }}{\text { Eq.wt.of metal } 2}$

i.e., $\frac{m_{1}}{m_{2}}=\frac{E_{1}}{E_{2}}$

Hence, $ E_{1}=\frac{m_{1}}{m_{2}} \times E_{2}$