Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If log 2=0.3010, and log 3=0.4771 then log 150=
Q. If
lo
g
2
=
0.3010
, and
lo
g
3
=
0.4771
then
lo
g
150
=
178
137
Logarithms
Report Error
A
2.1761
B
2.8751
C
2.5762
D
2.6126
Solution:
(i) Express as product of powers of 2 and 3 then use the values of
lo
g
2
and
lo
g
3
.
(ii)
lo
g
150
=
2
lo
g
5
+
lo
g
2
+
lo
g
3
.
(iii) Also,
lo
g
5
=
lo
g
10
−
lo
g
2
.