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  4. If log 2=0.3010, and log 3=0.4771 then log 150=

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Q. If $\log 2=0.3010$, and $\log 3=0.4771$ then $\log 150=$

Logarithms

Solution:

(i) Express as product of powers of 2 and 3 then use the values of $\log 2$ and $\log 3$.
(ii) $\log 150=2 \log 5+\log 2+\log 3$.
(iii) Also, $\log 5=\log 10-\log 2$.